An amber mutant was grown in cells encoding an amber suppressor (permissive cells) and plated in normal cells (non-permissive) after a single burst to score the appearance of amber revertants (1).  An estimate of ms = 2.7 ´ 10-6 s/r was obtained using the null-class method.  There are eight possible ways of reverting an amber mutation through single nucleotide substitutions.  However, some might be lethal and hence not observable.  For pL = 0.2-0.4, Ts = 4.8-6.4.  Taking Ts = 5.6, ms/n/r = 3 ´ 2.7 ´ 10-6 / 5.6 = 1.4 ´ 10-6.  Error in this estimate comes mainly from the undetermined T-value, which could produce a maximal underestimation of 5.6-fold and a maximal overestimation of 1.4-fold.

 

 

    1.    Chao, L., C. U. Rang, and L. E. Wong. 2002. Distribution of spontaneous mutants and inferences about the replication mode of the RNA bacteriophage f6. J. Virol. 76:3276-3281.