An amber mutant was grown in cells encoding an
amber suppressor (permissive cells) and plated in normal cells (non-permissive)
after a single burst to score the appearance of amber revertants (1). An estimate of ms = 2.7 ´ 10-6 s/r was obtained using the null-class
method. There are eight possible ways of
reverting an amber mutation through single nucleotide
substitutions. However, some might be
lethal and hence not observable. For pL = 0.2-0.4, Ts = 4.8-6.4. Taking
Ts = 5.6, ms/n/r =
3 ´ 2.7 ´ 10-6 / 5.6 = 1.4 ´ 10-6. Error
in this estimate comes mainly from the undetermined T-value, which could produce a maximal underestimation of 5.6-fold
and a maximal overestimation of 1.4-fold.
1. Chao, L., C. U. Rang, and L. E. Wong. 2002.
Distribution of spontaneous mutants and inferences about the replication mode
of the RNA bacteriophage f6. J. Virol. 76:3276-3281.