This redox reaction involves the nucleophilic attack of the terminal sulfur of the thiosulfate anion to the iodine molecule, that undergoes heterolytic cleavage. After that, another thiosulfate anion attacks the sulfur atom linked to iodine, eliminating an I- and forming the [O3S-SS-SO3]2- anion (tetrathionate) .
This redox reaction is first order for O2 and second order for NO. The proposed mechanism implies a consecutive attack of the two molecules of NO followed by cleavage of the O-O bond.
In this redox reaction there is oxygen transfer between two ione ClO- anions.
In this redox reaction there are two consecutive oxygen transfers